629A - Far Relative’s Birthday Cake - CodeForces Solution

brute force combinatorics constructive algorithms implementation *800

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Python Code: 

from math import factorial

n = int(input())

matrix = list()
for i in range(n):
    matrix.append(input())

happiness_count = 0
for i in range(len(matrix)):
    col_chocolate = 0
    for j in range(len(matrix[i])):
        if (matrix[i][j] == 'C'):
            col_chocolate += 1
    happiness_count += col_chocolate * (col_chocolate - 1) / (2 * 1)

for j in range(len(matrix[0])):
    row_chocolate = 0
    for i in range(len(matrix)):
        if (matrix[i][j] == 'C'):
            row_chocolate += 1
    happiness_count += row_chocolate * (row_chocolate - 1) / (2 * 1)
            
print(int(happiness_count))

C++ Code: 

#include <bits/stdc++.h>

using namespace std;
string a[105];
int main()
{
    int n, ans = 0;
	cin >> n;
    for(int i = 0; i < n; ++i)
    {
        cin >> a[i];
    }
    for(int i = 0; i < n; ++i)
    {
        int cnt = 0;
		for(int j = 0; j < n; j++)
		{
			if(a[i][j] == 'C')
			{
			    cnt++;
			}
		}
        ans += (cnt - 1) * cnt / 2;
        cnt = 0;
        for(int j = 0; j < n; j++)
		{
			if(a[j][i] == 'C') 
			{
			     cnt++;
			}
		}
		ans += (cnt - 1) * cnt / 2;
    }
    cout << ans << "\n";
    return 0;
}
/* Thu Feb 09 2023 17:16:59 GMT+0300 (Moscow Standard Time) */


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